[tan A+cot A],[(1-cot A)quad (1-tan A]

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA

(tan A) / (1-cot A) + (cot A) / (1-tan A) = 1 + tan A + cot A = 1 + sec A cos ecA (1 + cos theta + sin theta) / (1 + cos theta-sin theta) = (1 + sin theta) / (cos theta)

Prove that (tan A) / (1-cot A) + (cot A) / (1-tan A) = sec A cos ecA + 1

Prove the following identities: (tan A)/(1-cot A)+(cot A)/(1-tan A)=1+tan A+cot A=1+sec A cos ecA

Find (tan A)/((1-cot A))+(cot A)/((1-tan A))

Prove that : (tan A)/ (1 - cot A) + (cot A)/ (1 - tan A) = sec A cosec A + 1

The expression (tan A)/(1- cot A) + ( cot A )/( 1- tan A) can be written as