The position vector of a particle is `vec( r) = a cos omega t i + a sin omega t j`, the velocity of the particle is

The position vector of a particle is vecr = (a cos omega t)hati + (a sin omegat)hatj . the velocity of the particle is

The position vector of a particle is r = a sin omega t hati +a cos omega t hatj The velocity of the particle is

The position vector of a particle is r = a sin omega t hati +a cos omega t hatj The velocity of the particle is

The motion of a particle is given by x = A sin omega t + B os omega t . The motion of the particle is

The motion of a particle is given x = A sin omega t + B cos omega t The motion of the particle is

The position vector of a particle is given by vec(r ) = k cos omega hat(i) + k sin omega hat(j) = x hat(i) + yhat(j) , where k and omega are constants and t time. Find the angle between the position vector and the velocity vector. Also determine the trajectory of the particle.

A particle is moving in a circle of radius r with constant angular velocity omega . At any point (r, theta ) on its path , its position vector is vec(r ) = r cos theta hat(i) + r sin theta hat(j) . Show that the velocity of the particle has no component along the radius.

The position vector of a particle moving in a plane is given by r =a cos omega t hati + b sin omega I hatj, where hati and hatj are the unit vectors along the rectangular axes C and Y : a,b, and omega are constants and t is time. The acceleration of the particle is directed along the vector