Home
Class 9
MATHS
ABCD is a parallelogram and O is the poi...

ABCD is a parallelogram and O is the point of intersection of its diagonals. If `ar(triangle AOD)= 4cm^2` find `ar(triangle AOB)`

Text Solution

Verified by Experts

ABCD is a parallelogram
Diagonal AC and BD bisects each other.
Mid point of AC=Midpoint of BD
O is bisect BD in two part.
AO is themedian of`/_ABD`
Median divides the area of triangle `/_ABD` in two equals parts.
area of`/_AOD= area of`/_AOB``
A=area of`/_AOB`
...
Promotional Banner

Similar Questions

Explore conceptually related problems

In the figure. ABCD is a parallelogram and O is any point on BC . Prove that ar (triangleABO) + ar (triangleDOC) = ar(triangleODA)

ABCD is a parallelogram and O is a point in its interior. Prove that (i) ar(triangleAOB)+ar(triangleCOD) =(1)/(2)ar("||gm ABCD"). (ii) ar(triangleAOB)+ar(triangleCOD)=ar(triangleAOD)+ar(triangleBOC) .

ABCD is a parallelogram. P is any point on CD. If ar(triangleDPA) = 15 cm^2 and ar(triangleAPC) = 20 cm^2 , the ar (triangleAPB) =

ABCD is a parallelogram and X is the mid-point of AB. If ar (AXCD) = 24 cm^2 , then ar (ABC) = 24 cm^2 .

ABCD is a parallelogram,P is the mid point of AB.BD and CP intersects at Q such that CQ:QP=3:1. If ar(Delta PBQ)=10cm^(2), find the area of parallelogram ABCD.

The sides AD, BC of a trapezium. ABCD are parallel and the diagonals AC and BD meet at O. If the area of triangle AOB is 3 cm and the area of triangle BDC is 8 cm2, then what is the area of triangle AOD?

In the figure ABCD is a trapezium. Diagonal AC and BD intersect at O. Area of triangle A B C is 24 cm^2 and area of triangle AOB is 10 sq.cm. a) Find the area of triangle BOC. b) How much is the area of triangle AOD? Write reason.

In the given figure, ABCD is a ||gm in which diagonals AC and BD intersect at O. If ar(||gm ABCD) is 52 cm^(2) then the ar(triangleAOB) =?

In the given fig. ABCD is a parallelogram and ABE is a triangle. Also AB||CE . If ar (ABCD) = 60 cm^2 then ar (DeltaABE) is :

PQRS and ABRS are parallelograms and X is any point on the side BR. Show that ar (Delta AXS) = (1)/(2) ar (PQRS)