[" 23."2(ax-by)+a+4b=0],[" BSE "2002Clquad 2(bx+ay)+b-4a=0quad [CBSE2004]]

2(ax-by)+(a+4b)=0,2(bx+ay)+(b-4a)=0

ax+by=a+b bx+ay=b^2

Solve: ax+by=a-b,quad bx-ay=a+b

(bx)/(a)-(ay)/(b)+a+b=0 and bx-ay+2ab

The straight line x-y-2=0 cuts the axis of x at A. It is rotated about A in such a manner that it is perpendicular to ax+by+c=0. Its equation is: (a) bx-ay-2b=0 (b) ax-by-2a=0 (c) bx+ay-2b=0 (d) ax+by+2a=0

ax+by=a-b;bx-ay=a+b

Solve: ax + by = a - b bx - ay = a + b

Solve the following pair of linear equations 2(ax-by)+(a+4b)=02(bx+ay)+(b-40=0

The equation of a line perpendicular to line ax+by+c=0 and passing through (a,b) is equal to ................ A) bx-ay=0 B) bx+ay-2ab=0 C) bx+ay=0 D) bx-ay+ 2ab=0