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Solve the equation for x 5^(2x+1)=6. 5^...

Solve the equation for `x` `5^(2x+1)=6. 5^x-1`

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Given:`5^(2x+1)=6. 5^x-1`
`5^(2x)xx5=6xx5^(x)-1`
`5(5^x)^2-6(5^x)+1=0`
put `5^x=t`
`5t^2-6t+1=0`
`5t^2-5t-t+1=0`
`5t(t-1)-1(t-1)=0`
`t=1/5,1=5^-1,5^0`
`x=-1,0`
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