If `1176=2^a xx\ 3^b xx\ 7^c ,` and `a , b\ a n d\ c` are natural numbers. find a,b,c.

Explanation

To solve the problem of finding the values of \( a \), \( b \), and \( c \) in the equation \( 1176 = 2^a \times 3^b \times 7^c \), we need to factor the number 1176 into its prime factors. Here’s a step-by-step solution:

### Step 1: Start Dividing by the Smallest Prime Number
We will start by dividing 1176 by the smallest prime number, which is 2.

\[ 1176 \div 2 = 588 \]
...