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RD SHARMA-EXPONENTS OF REAL NUMBER-All Questions
- [{(625)^(-1/4)}^(-1/2)]^2
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- Simplify: (256)^-(4^(((-3)/2)))
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- Simplify: 4/((216)^(-2/3))+1/((256)^(-3/4))+2/((243)^(-1/5))
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- Simplify: sqrt(1/4)+(0. 01)^(-1/2)-(27)^(2/3)
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- Simplify ((25)^(3/2)xx(243)^(3/5))/((16)^(5/4)xx(8)^(4/3)) (16xx 2^(n...
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- Simplify: ((81)/(16))^(-3/4)xx[((25)/9)^((-3)/2)-:(5/2)^(-3)]
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- Simplify each of the following by removing radical signs and negative ...
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- Simplify each of the following by removing radical signs and negative ...
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- Assuming that x , y , z are positive real numbers, simplify each of th...
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- Assuming that x , y , z are positive real numbers, simplify each of th...
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- Assuming that x , y , z are positive real numbers, simplify each of th...
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- If x , y ,z are positive real numbers show that: sqrt(x^(-1)y)dotsqrt(...
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- If ((x^(-1)y^2)/(x^3y^(-2)))^1.\ ((x^6\ y^(-3))/(x^2\ y^3))^(1/2)=x^a ...
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- If x= 28^(1/3) and y= 27^(1/3) find the value of x+y-1/(x^2+x y+y^2)
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- If x=3,\ find the value of (x^(1/3)+\ x^(-1/3))\ (x^(2/3)+x^(-2/3)-1\...
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- If 25^(n-1) + 100 = 5^ (2n-1), find the value of n :
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- Solve the equation for x : (i)\ 4^(2x)=1/(32) (ii)\ sqrt((3/5)^(1-...
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- Solve the equation for x : (5^0+2/3)^2 3=(0. 6)^(3-2x)
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- Solve the equation for x : 2^3(5^0+3^(2x))=\ 8 8/(27)
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- Solve the equation: 3(2^x+1)-2^(x+2)+5=0
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