Solve the equation for `x\ a n d\ y` `(32)^x-:2^(y+1)=1,\ 16^(4-x/2)-8^y=0`

Explanation

To solve the equations for \( x \) and \( y \):

1. **Write down the equations**:
\[ (32)^x - 2^{(y+1)} = 1 \]
\[
16^{(4 - \frac{x}{2})} - 8^y = 0
...