An artificial satellite of mass 200 kg, revolves around the earth in an orbit of average radius 6670 km. What is its orbital kinetic energy ? `[M_("earth")=6xx10^(24)kg, G=6.67xx10^(-11)N-m^(2)//kg^(2)]`

If a satellite of mass 400 kg revolves around the earth in an orbit with speed 200 m/s then its potential energy is

If a satellite of mass 400 kg revolves around the earth in an orbit with speed 200 m/s then its potential energy is

If a satellite of mass 400 kg revolves around the earth in an orbit with speed 200 m/s then its potential energy is

An artificial satellite revolves round the earth at a height of 1000 km . The radius of the earth is 6.38xx10^(3)km . Mass of the earth 6xx10^(24)kg,G=6.67xx10^(-11)Nm^(2)kg^(-2) . Find the orbital speed and period of revolution of the satellite.

Calculate (i) kinetic energy (ii) potential energy and (iii) total energy of a satellite of mass 200 kg orbiting around the earth in an orbit of height 100 km from the surface of earth. Given, mass of earth = 10^(25) kg ,radius of earth = 6.4 xx 10^(6) m, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

A satellite of mass 200 kg revolves around of mass 5 xx 10^(30) kg In a circular orbit of radius 6.6 xx10^(6) m . Binding energy of the satellite is

A satellite of mass 200 kg revolves around of mass 5 xx 10^(30) kg In a circular orbit of radius 6.6 xx10^(6) m . Binding energy of the satellite is

A satellite revolves around the earth at a height of 1000 km. The radius of the earth is 6.38 xx 10^(3) km. Mass of the earth is 6xx10^(24)kg and G=6.67xx10^(-14)"N-m"^(2)kg^(-2) . Determine its orbital velocity and period of revolution.

A satellite of mass 2000 kg is revolving around the earth in a circular orbit of radius 4xx10^(4) km. The gravitational force exerted by the satellite on the earth is ________. [Mass of the earth = 6xx10^(24)kg, G=6.67xx10^(-11)Nm^(2)//kg^(2) ]