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Prove that: ((64)/(125))^(-2/3)+1/(((256...

Prove that: `((64)/(125))^(-2/3)+1/(((256)/(625))^(1/4))+\ ((sqrt(25))/(root(3)64))=(65)/(16)`

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To prove that \[ \left(\frac{64}{125}\right)^{-\frac{2}{3}} + \frac{1}{\left(\frac{256}{625}\right)^{\frac{1}{4}}} + \frac{\sqrt{25}}{\sqrt[3]{64}} = \frac{65}{16}, \] we will simplify each term step by step. ...
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Prove that . (i) [8^(-(2)/(3)) xx 2^((1)/(2))xx 25^(-(5)/(4))] div[32^(-(2)/(5)) xx 125 ^(-(5)/(6)) ] = sqrt(2) (ii) ((64)/(125))^(-(2)/(3)) = (1)/(((256)/(625))^((1)/(4)))+ (sqrt(25))/(root3(64)) = (65)/(16) (iii) [7{(81)^((1)/(4)) +(256)^((1)/(4))}^((1)/(4))]^(4) = 16807 .

Find the value of (9^(3//2)-3xx5^(0)-[(1)/(81)]^(-1//2))/(((64)/(125))^(-2//3)+(1)/(((256)/(625))^(1//4))+((sqrt(25))/(root(3)(64)))) .

(64/125)^(-2/3)+(256/625)^(-1/4)+(3/7)^0=

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Evaluate root3((-64)/(125))

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(1) (4)/((216)^((2)/(3)))+(1)/((256)^((3)/(4)))+(2)/((243)^((1)/(5))) (ii) ((64)/(125))^((2)/(3))+((256)/(625))^((1)/(4))+((3)/(7))^(0) (iii) ((81)/(16))^((3)/(4))(((25)/(9))^((3)/(2))-:((5)/(2))^(-3)) (iv) ((25)^((5)/(2))times(729)^((1)/(3)))/((125)^((2)/(3))times(27)^((2)/(3))times8^((4)/(3)))

{((216)/(64))^((2)/(3))*(((256)/(81))^(-(1)/(4)))/(((16)/(144))^(-(1)/(2)))}^((1)/(2))

Factorise (64)/(125)a^3-(96)/(25)a^2+(48)/(5)a-8

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