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Find the value of `x` in each of the following: `(i)\ (3/5)^x\ (5/3)^(2x)=(125)/(27)` `\(ii)\ 5^(x-2)\ xx\ 3^(2x-3)=135`

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(i)`(3/5)^x (5/3)^(2x)=(125)/(27)`
`(5/3)^(-x) (5/3)^(2x)=(5/3)^3`
`(5/3)^x=(5/3)^3`
so `x=3`
(ii) `5^(x-2) xx3^(2x-3)=135`
`5^(x-2) xx3^(2x-3)=5xx3^3`
on comparing bothside we have `x-2=1` and `2x-3=3` so `x=3`
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