Consider the ray diagram for the refraction given Fig. The maximum value of angle `theta` for which the light suffers total internal reflection at the vertical surface, is.
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Consider the situation shown in figure. Find the maximum angle theta for which the light suffers total internal reflection at the vertical surface.

Consider the situation shown in figure. Find the maximum angle theta for which the light suffers total internal reflection at the vertical surface.

Consider the situation shown in figure. Find the maximum angle theta for which the light suffers total internal reflection at the vertical surface.

In Fig., find the maximum angle i for which light suffers total internal reflection at the vertical surface. .

In Fig. find the maximum angle i for which light suffers total internal reflection at the vertical surface.

Draw a ray diagram to show the total internal reflection.

A ray of light can suffer total internal refraction only when it goes from

A light rays is incident on a prism of prism angle A and refractive index mu . Show that the smallest value of the angle of incidence for which the reflected ray does not suffer total internal reflection at the second face, i.e. just comes out of it, is given by i=sin^-1[(mu^2-1)^(1//2)sinA-cosA] .

Light is incident at point A on one of the faces of a diamond crystal (mu = 2.0) . Find the maximum allowed value of angle of incidence theta so that light suffers total internal reflection at point B.