If `8^(x+1)=64 ,` what is the value of `3^(2x+1)` ? 1 (b) 3 (c) 9 (d) 27

Explanation

`8^(x+1)=64`
`=8^(x+1)=8^2`
Comparing, we get;
`x+1=2`
`=x=2−1=1`
Now
`3^(2x+1)`
`=3^(2×1+1)`
`=3^(2+1)`
`=3^3`
`=3×3×3`
`=27`
`therefore` The value of `3^(2x+1)=27`