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Two supplementary angles differ by 48...

Two supplementary angles differ by `48^0` . Find the angles.

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To solve the problem of finding two supplementary angles that differ by \(48^\circ\), we can follow these steps: ### Step 1: Define the Angles Let the two angles be \(A\) and \(B\). According to the problem, we know that: - \(A + B = 180^\circ\) (because they are supplementary) - \(B - A = 48^\circ\) (because they differ by \(48^\circ\)) ### Step 2: Express One Angle in Terms of the Other ...
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RD SHARMA-LINES AND ANGLES -All Questions
  1. If an angle is 30^0 more than one half of its complement, find the ...

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  2. Two supplementary angles are in the ratio 4:5 . Find the angles.

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  3. Two supplementary angles differ by 48^0 . Find the angles.

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  4. An angle is equal to 8 times its complement. Determine its measure.

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  5. If the angles (2x-10)^0 and (x-5)^0 are complementary angles, find xdo...

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  6. If the complement of an angle is equal to the supplement of the thr...

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  7. If an angle differs from its complement by 10^0 , find the angle.

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  8. If the supplement of an angle is three times its complement, find t...

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  9. If the supplement of an angle is two-third of itself. Determine the...

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  10. An angle is 14^0 more than its complementary angle. What is its mea...

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  11. The measure of an angle is twice the measure of its supplementary a...

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  12. The bisectors of base angles of a triangle cannot enclose a right an...

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  13. If the bisectors of the base angles of a triangle enclose an angle o...

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  14. In a parallelogram A B C D diagonals A C\ a n d\ B D intersect at O\ a...

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  15. In Fig. 6.13, lines AB and CD intersect at O. If /A O C\ +/B O E=70^@...

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  16. In figure, DeltaO D C~ DeltaO B A ,/B O C=125^oand /C D O=70^o. Fin...

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  17. In Fig. 6.13, lines AB and CD intersect at O. If /A O C\ +/B O E=70^@...

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  18. In Figure, lines X Y\ a n d\ M N intersect at O. If /P O Y=90^0a n d\ ...

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  19. In Figure, /P Q R=\ /P R Q , then prove that /P Q S=\ /P R Tdot

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  20. If ray O C stands on line A B such that /A O C=/C O B , then show that...

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