The opposite sides of a quadrilateral are parallel. If one angle of the quadrilateral is `60^@,` find the other angles.

Explanation

Solution:
Given,'AB∣∣CD'
Also, '/_A=60'
We know that
`/_A+/_B=180 ^@`___(i) [Co-interior angle are supplementary]
`/_B+/_C=180^@` __(ii) [Co-interior angle are supplementary]
Then, from (i) & (ii)`,/_A=/_C`
Similarly, `/_B=/_D`
From equation (i)
`60^@+/_B=180^@`
Then, `'/_B=120^@'`
Other angles are `'120^@,60^@,120^@'`