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If Figure, arms BA and BC OF /A B C are...

If Figure, arms `BA and BC ` OF `/_A B C` are respectively parallel to arms `ED` and` EF` or `/_D E F` . Prove that `/_A B C=/_D E F`

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Given: In `'/_ABC' and '/_DEF' 'BA ||ED' and 'BC || EF'
To prove:/_ABC +/_DEF=180^@'`
Construction : Produce 'BC' to 'H' intersecting 'ED' at 'G'
Proof:
∵'AB || ED'
∴`'/_ABC =/_EGH'`...(i) (Corresponding angles)
∵`'/_EGH +/_DEF =180^@` (Sum of co-interior angles)
⇒`/_ABC +∠DEF =180^@`[From(i)]
Hence proved.
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