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Two complementary angles are such that...

Two complementary angles are such that two times the measure of one is equal to three times the measure of the other. The measure of the smaller angle is (a) `45^@` (b) `30^@` (c) `36^@` (d) none of these

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Let one angle be xº.
Then, the other complementary angle becomes `(90 - x)°`
It is given that two times the angle measuring `xº` is equal to three times the angle measuring `(90 - x)`
Or, we can say that:
`2x = 3(90-x)`
`2x = 270 - 3x`
`2x + 3x = 270`
`5x = 270`
On dividing both sides of the equation by `5`,we get
`270/ 5= x `
=`x = 54 `
Also, the other complementary angle becomes `90 -x`
= `90 -54`
= `36^@`
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