[" 29If "x=a(cos theta+theta sin theta)" and "y=a(sin theta-theta],[cos theta)," then find "(d^(2)y)/(dx^(2))]

If x=a(cos 2 theta+2 theta sin 2 theta) " and" y=a(sin 2 theta - 2 theta cos 2 theta) , find (d^(2)y)/(dx^(2)) " at" theta =(pi)/(8) .

If x=a(cos 2 theta+2 theta sin 2 theta) " and" y=a(sin 2 theta - 2 theta cos 2 theta) , find (d^(2)y)/(dx^(2)) " at" theta =(pi)/(8) .

If x = a (cos theta + theta sin theta), y = a(sin theta - theta cos theta) then (d^(2)y)/(dx^(2)) =

x = a (cos theta + theta sin theta), y = a (sin theta - theta cos theta) . then find dy/dx

If x = a (cos theta + theta sin theta) and y = a (sin theta - theta cos theta) , find (d^2y)/(dx^2) at t = pi/4 .

If x = cos theta + theta sin theta, y = sin theta - theta cos theta then (d ^(2) y)/(dx ^(2)) =

If x =a (cos theta + theta sin theta ), y =a (sin theta - theta cos theta ) then (dy)/(dx) =