In a ` A B C ,` if `2/_A=3/_b=6\ /_c ,` determine `/_A ,\ /_B\ a n d\ /_C`

Explanation

`2angleA = 3 angle B
A = 3B/2`
`3B=6C
C=B/2`
Now
`A+B+C=180° (angle sum property of A)
3B/2+B+B/2 = 180°
=>(3B+2B+B)/2 = 180°
=>6B/2 = 180°
=> 6B = 180×2
=> 6B = 360°
=> B = 360/6
=> B = 60°`