In Figure, A B D C . If x=(4y)/3a n d\ ...

In Figure, `A B D C` . If `x=(4y)/3a n d\ y=(3z)/8,` find `/_B C D ,\ /_A B C\ a n d\ /_B A D`

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`ABIICD`
`=>x + y + z = 180^@`
`=> (4y)/3 + y + (8y)/3 = 180^@`
`=> 4y + 3y + 8y = 540^@ `
`=> 15y = 540`
`=> y = 36`
`x=(4y)/3=4* 36/3 = 48`
`x = 48z=(8y)/3=8xx36/3 = 96`
`z =96`
` /_BCD = z = 96^@`
`/_ABC=x+y=48 +36=84^@`
`/_BAD =180-x-72`
`= 180 - 48-72= 60^@`

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