In Figure `P S\ ` is the bisector of `/_Q P R\ a n d\ P T\ _|_Q R` . Show that `/_T P S=1/2(/_Q-/_R)`

Explanation

To solve the problem, we need to show that \( \angle TPS = \frac{1}{2}(\angle Q - \angle R) \) given that \( PS \) is the bisector of \( \angle QPR \) and \( PT \perp QR \).

### Step-by-Step Solution:

1. **Identify the Given Information:**
- \( PS \) is the bisector of \( \angle QPR \).
- \( PT \) is perpendicular to \( QR \).

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