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The angle of a triangle are arranged in ascending order of magnitude. If the difference between two consecutive angles is `10^0,` find the three angles.

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Solution:
Let one angle of a triangle be 'x'.
Second angle will be 'x + 10'.
Third angle will be 'x + 20'.
Using theorem, Sum of interior angles of a triangle is '180@'.
Hence ' /_A+/_B+ /_C=180@'
⇒ 'x + x + 10 + x + 20 = 180@'
⇒ '3x + 30 = 180@'
⇒'x = 50@'
:.Angles are '50@,60@,70@'
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