In Figure, `A B` divides `/_D A C` in the ratio `1\ :3\ a n d\ A B=D Bdot` Determine the value of `x`

Explanation

Solution
`/_DAC=180@−108@=72@`
`/_BAC /_DAB =1/3`
Given
⇒`/_DAB=3/_BAC`
∴`/_BAC+/_DAB=/_DAC=72@`
⇒`/_BAC+3/_BAC=72@`
⇒`4/_BAC=72@`
⇒`/_BAC= 72/4=18@`
∴`/_DAB=3×18@=54@`
∴`/_DAB=/_BDA=54@(AB=DB)`
∴`/_ABD=180@−(54@+54@)`
= 180@−108@`
=`72@`
No, '/_DBA=72@=/_BAC+x`(Exterio angle)
⇒`x=72@−18@=54@`