side B C\ of A B C is produced to poin...

side `B C\ ` of ` A B C` is produced to point `D` such that bisectors of `/_A B C\ a n d\ /_A C D` meet at a point `Edot` If `/_B A C=68^0,` find `/_B E C`

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`/_FGH =125@ and /_B = 55@
/_FGH+/_ FGE= 180@ (Linear pair)
125 + y = 180@
y= 180-125" = 55@
BA| | FD and BD || FG
/_B =/_ F = 55@
Now in /_\EFG,
/_F +/_FEG + /_FGE=180@`
(Angles of a triangle)
= `55 +x +55' 180@
=x+110@= 180@
x=180-110@= 70@
Hence x=70,y=55@`

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