An exterior angle of a triangle is equal to `100^0` and two interior opposite angles are equal. Each of these angles is equal to `75^0` (b) `80^0` (c) `40^0` (d) `50^0`

Explanation

It is given that the exterior angle of the triangle is 100° and two of the interior opposite angles are equal.So, /_ACD= 100@ and /_A=/_B
So, now using the property, "an exterior angle of the triangle is equal to the sum of the two opposite interior angles", we get.
In `/_\ABC
/_A+/_B =/_ACD
/_(2A) = 100
`/_A= (100)/2
/_A = 50
/_A= B = 50@`
Therefore, each of the two opposite interior angles is ``50@.