In a ` A B C ,` if `/_A=60^0,\ /_B=80^0` and the bisectors of `/_B\ a n d\ /_C` meet at `O ,` then `/_B O C=` `60^0` (b) `120^0` (c) `150^0` (d) `30^0`

Explanation

To find the angle \( \angle BOC \) in triangle \( ABC \) where \( \angle A = 60^\circ \) and \( \angle B = 80^\circ \), we can follow these steps:

### Step 1: Find Angle C
First, we need to find the measure of angle \( C \) using the triangle sum property. The sum of the angles in a triangle is \( 180^\circ \).

\[ \angle A + \angle B + \angle C = 180^\circ \]
...