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`(sintheta)/(1-cottheta)+(costheta)/(1-tantheta)` is equal to (a) 0 (b) 1 (c) `sintheta+costheta` (d) `sintheta-costheta`

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  18. If x=asecthetacosvarphi , y=bsecthetasinvarphi and z=ctantheta , then ...

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