Home
Class 12
PHYSICS
[" A particle is moving in an isolated "...

[" A particle is moving in an isolated "x-y" plane.At an instant,the particle "],[" has velocity "(4i+4)" mis and acceleration "(3i+5i)" mis? At that instant "],[" what will be the radius of curvature of the path? "],[[" (A) "16sqrt(2)m," (B) "15m],[" (C) "18m," (D) None of these "]]

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is moving in an isolated x-y plane. At an instant, the particle has velocity (4hati+4hatj)m//s and acceleration (3hati+5hatj)m//s^(2) . At that instant what will be the radius of curvature of its path ?

A particle is moving in x-y plane. At an instant, it has velocity (4 hat (i) + 4 hat(j)) m//s and acceleration (3 hat(i) + 5 hat(j)) m//s^(2) At that instant, the radius of curvature of its path will be :

A particle is moving in x-y plane. At an instant, it has velocity (4 hat (i) + 4 hat(j)) m//s and acceleration (3 hat(i) + 5 hat(j)) m//s^(2) At that instant, the radius of curvature of its path will be :

A particle starts moving with velocity "vecV=hat i(m/s)", and acceleration "vec a=(hat i+hat j)(m/s^(2))".Find the radius of curvature of the particle at "t=1sec".

A particle is moving in such a way that at one instant velocity vector of the particle is 3hati+4hatj m//s and acceleration vector is -25hati - 25hatj m//s ? The radius of curvature of the trajectory of the particle at that instant is

A particle is moving in such a way that at one instant velocity vector of the particle is 3hati+4hatj m//s and acceleration vector is -25hati - 25hatj m//s ? The radius of curvature of the trajectory of the particle at that instant is

A particle is moving on a circle of radius A .At an instant its speed and tangential acceleration are B and C respectively.Total acceleration of the particle at that instant is

The position of a particle at any point instant is x . Find the velocity and acceleration at any instant .

Initial velocity and acceleration of a particles are as shown in the figure. Acceleration vector of particle remain constant. Then radius of curvature of path of particle :