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let f : R to Rbe defined by f (x) =2x +6...

let `f : R to R`be defined by `f (x) =2x +6` which is a bijective mapping, then `f ^(-1) (x)` is given by

A

`2x+6`

B

`6x+2`

C

`x/2-3`

D

`x-3`

Text Solution

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The correct Answer is:
C
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