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If f: R rarr R be defined by f(x) =e^(x...

If f: R `rarr` R be defined by `f(x) =e^(x)` and g:R `rarr` R be defined by g(x) =`x^(2)` the mapping gof : R `rarr` R be defined by (gof)(x) =g[f(x)] `forall x in R` then

A

gof is bijective but f is not injective

B

gof is injective and g is injective

C

gof is injective but g is not bijective gof is surjective and g is surjective

D

gof is injective and g is injective

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The correct Answer is:
C
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TARGET PUBLICATION-SETS, RELATIONS AND FUNCTIONS-COMPETITVE THINKING
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