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f(x)={(x", if x is rational"),(0", ...

`f(x)={(x", if x is rational"),(0", if x is irrational"):}, g(x)={(0", if x is rational"),(x", if x is irrational"):}`
Then, `f-g` is

A

one-one and onto

B

one-one end into

C

many one and onto

D

neither one-one nor onto

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Verified by Experts

The correct Answer is:
A
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