In DeltaABC,1-tan.(A)/(2)tan.(B)/(2)=...

In `DeltaABC,1-tan.(A)/(2)tan.(B)/(2)`=

A

`(2c)/(a+b+c)`

B

`(a)/(a+b+c)`

C

`(2)/(a+b+c)`

D

`(4a)/(a+b+c)`

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The correct Answer is:

A

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