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If (a)/(b)tanxgt-1,"then "tan^(-1)[(acos...

If `(a)/(b)tanxgt-1,"then "tan^(-1)[(acosx-bsinx)/(bcosx+asinx)]` is

A

`tan^(-1)((a)/(b)-x)`

B

`cot^(-1).(a)/(b)x`

C

`tan^(-1).(a)/(b)-x`

D

`cot^(-1)((a)/(b)-x)`

Text Solution

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The correct Answer is:
C
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tan^(-1)((a+bcosx)/(b-acosx))

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Find the differentiation of y=tan^(-1)((acosx-bsinx)/(bcosx+asinx))

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int((acosx-bsinx)dx)/((a sin x+b cos x)^(2))

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