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In a DeltaABC,angleC=(pi)/(3),"then "(3)...

In a `DeltaABC,angleC=(pi)/(3),"then "(3)/(a+b+c)-(1)/(a+c)=`

A

`(1)/(a+b)`

B

`(1)/(b+c)`

C

`(1)/(2a+b)`

D

`(1)/(b+2c)`

Text Solution

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The correct Answer is:
B
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