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In any DeltaABC under usual notation, a(...

In any `DeltaABC` under usual notation, `a(bcosC-c cosB)`=

A

`b^(2)-c^(2)`

B

`c^(2)-b^(2)`

C

`(b^(2)-c^(2))/(2)`

D

`(c^(2)-b^(2))/(2)`

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A
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