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Let PQR be a triangle of area Delta with...

Let `PQR` be a triangle of area `Delta` with `a = 2, b = 7/2 and c =5/2,` where `a, b and c` are the lengths of the sides of the triangle opposite to the angles at `P, Q and R` respectively. Then `(2sinP-sin2P)/(2sinP+sin2P)` equals

A

`(3)/(4Delta)`

B

`(45)/(4Delta)`

C

`((3)/(4Delta))^(2)`

D

`((45)/(4Delta))^(2)`

Text Solution

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The correct Answer is:
C
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