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If the lines joining the origin and the point of intersection of curves `a x^2+2h x y+b y^2+2gx+0` and `a_1x^2+2h_1x y+b_1y^2+2g_1x=0` are mutually perpendicular, then prove that `g(a_1+b_1)=g_1(a+b)dot`

A

`ag+a_(1)g_(1)=bg+b_(1)g_(1)`

B

`a+b="gg"_(1)(a_(1)+b_(1))`

C

`g(a_(1)+b_(1))=g_(1)(a+b)`

D

`g(a+b)=g_(1)(a_(1)+b_(1))`

Text Solution

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The correct Answer is:
C
NA
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