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The moment of inertia of a solid cylinde...

The moment of inertia of a solid cylinder of mass M, length 2R and radius R about an axis passing through the centre of mass and perpendicular to the axis of the cylinder is `I_(1)` and about an axis passing through one end of the cylinder and perpendicular to the axis of cylinder is `I_(2)`

A

`I_(2)-I_(1)=MR^(2)`

B

`(I_(1))/(I_(2))=(11)/(5)`

C

`(I_(2))/(I_(1))=(19)/(12)`

D

`I_(1)-I_(2)=MR^(2)`

Text Solution

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The correct Answer is:
A
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