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The moment of inertia of a solid cylinde...

The moment of inertia of a solid cylinder of mass M, length 2 R and radius R about an axis passing through the centre of mass and perpendicular to the axis of the cylinder is I, and about an axis passing through one end of the cylinder and perpendicular to the axis of cylinder is `I_2` then

A

`I_(2) gt I_(1)`

B

`I_(2)-I_(1)=MR^2`

C

`(I_(2))/(I_(1))=(19)/(12)`

D

`(I_(2))/(I_(1))=7/6`

Text Solution

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The correct Answer is:
B,A
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