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In Young's double slit experiment, the 8...

In Young's double slit experiment, the 8th maximum with wavelength `lambda_1` is at a distance `d_1` from the central maximum and the 6th maximum with a wavelength `lambda_2` is at a distance `d_2`. Then `(d_1//d_2)` is equal to

A

`4/3 (lamda_(2))/(lamda_(1))`

B

`4/3 (lamda_(1))/(lamda_(2))`

C

`3/4 (lamda_(2))/(lamda_(1))`

D

`3/4 (lamda_(1))/(lamda_(2))`

Text Solution

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The correct Answer is:
B

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TARGET PUBLICATION-INTERFERENCE AND DIFFRACTION-CRITICAL THINKING
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