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In the far field diffraction pattern of ...

In the far field diffraction pattern of a single slit under polychromatic illumination, the first minimum with the wavelength `lambda_1` is found to be coincident with third maximum at `lambda_2`. So

A

`3lamda_(1)=0.3 lamda_(2)`

B

`3 lamda_(1)=lamda_(2)`

C

`lamda_(1)=3.5lamda_(2)`

D

`0.3 lamda_(1)=3 lamda_(2)`

Text Solution

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The correct Answer is:
C
NA
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