In Young's double slit experiment, one of the slit is wider than other, so that amplitude of the light from one slit is double of that from other slit. If `I_m` be the maximum intensity, the resultant intensity I when they interfere at phase difference `phi` is given by:

Options

A. `(I_(m))/9(4+5cos phi)`
B. `(I_(m))/3(1+2"cos"^(2)(phi)/2)`
C. `(I_(m))/5(1+4"cos"^(2)(phi)/2)`
D. `(I_(m))/9(1+8"cos"^(2)(phi)/2)`

Answer

D

Explanation

NA