If a TV of rating 100 W operates for 6 hours per day, find the number of units consumed in a leap year.

Answer

The number of units consumed in any leap year is 219.6.

Explanation

`"Given: Power (P) = 100 W,"`
Time (t) = 6 hours / day for leap year,
`=6xx366" hours"`
`" …(leap year has 366 days)"`
`"To find: Number of units consumed in any leap year"`
`"Formula: Energy consumed "="Power"xx"time"`
Calculation: From formula,
`"Energy consumed "=100xx6xx366`
`=219600Wh`
`=(219600)/(1000)kWh`
`=219.6kWh`
As, 1 kWh = 1 unit
`therefore" "` 219.6 kWh is equal to 219.6 units.