Specific heat of water:

2kg ice at -20"^(@)C is mixed with 5kg water at 20"^(@)C . Then final amount of water in the mixture will be: [specific heat of ice =0.5 cal//gm "^(@)C , Specific heat of water =1 cal//gm"^(@)C , Latent heat of fusion of ice = 80 cal//gm]

Water of volume 4L in a closed container is heated with a coil of 2 kW. While water is heated, the container loses energy at a rate of 120 J/s. In how much time will the temperature of water rise from 27^(@)C to 77^(@)C ? (Specific heat of water is 4.2 kJ/kg and that of the container is negligible).

A heater melts 0^@C ice in a bucket completely into water in 6 minutes and then evaporates all that water into steam in 47 minutes 30 sec . If latent heat of fusion of ice is 80 cal//gram , latent heat of steam will be (specific heat of water is 1 cal//gam-^@C )

Stream at 100^(@)C is passed into 20 g of water at 10^(@)C . When water acquires a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water =1 cal g^(-1) .^(@)C^(-1) and latent heat of steam =540 cal g^(-1) ]

Steam at 100^(@)C is passed into 20 g of water at 10^(@)C when water acquire a temperature of 80^(@)C , the mass of water present will be [Take specific heat of water = 1 cal g^(-1).^(@) C^(-1) and latent heat of steam = 540 cal g^(-1) ]

The heat liberated when 1.89 g of benzoic acid is burnt in a bomb calorimeter at 25^(@)C increases the temperture of 18.94 kg of water by 0.632 ^(@)C . If the specific heat of water at 25^(@)C is 0.998 cal//g "deg" , the value of the heat of combustion of benzoic acid is

150 g of ice is mixed with 100 g of water at temperature 80^(@)C . The latent heat of ice is 80 cal/g and the specific heat of water is 1 cal//g-.^(@)C . Assuming no heat loss to the environment, the amount of ice which does not melt is –