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Two reactions R(2) and R(2) have identic...

Two reactions `R_(2) and R_(2)` have identical pre - exponential factors. Activations enery of `R_(1)` exceeds that of `R_(2)` by 10 kJ `mol_(-1)` . If `k_(1) and k_(2)` are rate constants for rate constants for reactions `R_(1) and R_(2)`
respectively at 300k , then In `(k_(2)/k_(1))`is equal to `(R=8.314 J mol^(-1)K^(-1))`

A

4

B

6

C

8

D

12

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The correct Answer is:
A
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Two reactions of the same order have equal pre exponential factors but their activation energies differ by 24.9kJ "mol"^(-1) . Calculate the ratio between the rate constants of these reactions at 27^(@)C . (Gas constant R = 8.314 J K^(-1) "mol"^(-1) )

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