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The rate law for a reaction between the ...

The rate law for a reaction between the substances A and B is given by
Rate = `k[A]^(n)[B]^(m)`
On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as:

A

`(1)/(2^((m+n))`

B

`(m+n)`

C

`(n-m)`

D

`2^((n-m))`

Text Solution

Verified by Experts

The correct Answer is:
D
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