`Ph-COOC_(2)H_(5)` on heating with dil. `H_(2)SO_(4)` produces _______.

Options

A. benzoic acid and ethyl alcohol
B. benzene and ethyl alcohol
C. benzenediazonium chloride and ethyl alcohol
D. benzoic acid and methyl alcohol

Answer

To solve the question, we need to analyze the compound given and the reaction conditions. The compound is Ph-COOC₂H₅, which is an ester known as ethyl benzoate. When ethyl benzoate is heated with dilute sulfuric acid (H₂SO₄), it undergoes hydrolysis. Here’s the step-by-step solution:

### Step 1: Identify the compound
The compound Ph-COOC₂H₅ is ethyl benzoate. It consists of a benzene ring (Ph) attached to a carboxylate group (COO) and an ethyl group (C₂H₅).

### Step 2: Understand the reaction
When an ester is treated with dilute sulfuric acid, it undergoes hydrolysis. Hydrolysis is a reaction with water that breaks the ester bond and produces an acid and an alcohol.

### Step 3: Write the hydrolysis reaction
The hydrolysis of ethyl benzoate can be represented as follows:
\[ \text{Ph-COOC}_2\text{H}_5 + \text{H}_2\text{O} \xrightarrow{\text{dil. H}_2\text{SO}_4} \text{Ph-COOH} + \text{C}_2\text{H}_5\text{OH} \]

### Step 4: Identify the products
From the reaction, we can see that the products are:
- Benzoic acid (Ph-COOH)
- Ethyl alcohol (C₂H₅OH)

### Step 5: Conclusion
Thus, the final products of heating ethyl benzoate with dilute sulfuric acid are benzoic acid and ethyl alcohol.

### Final Answer
**Benzoic acid and ethyl alcohol.**

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