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If A is a non-singular matrix of order n...

If A is a non-singular matrix of order n, then `A(adj A)=`

A

`A`

B

`I`

C

`|A|I_n`

D

`|A|^(2)I_n`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the expression for \( A \cdot \text{adj} A \) where \( A \) is a non-singular matrix of order \( n \). ### Step-by-Step Solution: 1. **Understanding Non-Singular Matrix**: A non-singular matrix \( A \) is one whose determinant is not equal to zero, i.e., \( \text{det}(A) \neq 0 \). 2. **Definition of Adjoint**: The adjoint (or adjugate) of a matrix \( A \), denoted as \( \text{adj} A \), is defined such that: \[ A \cdot \text{adj} A = \text{det}(A) \cdot I_n \] where \( I_n \) is the identity matrix of order \( n \). 3. **Applying the Definition**: Since \( A \) is non-singular, we can use the above property directly: \[ A \cdot \text{adj} A = \text{det}(A) \cdot I_n \] 4. **Conclusion**: Therefore, the expression \( A \cdot \text{adj} A \) simplifies to: \[ A \cdot \text{adj} A = \text{det}(A) \cdot I_n \] ### Final Answer: \[ A \cdot \text{adj} A = \text{det}(A) \cdot I_n \]
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Knowledge Check

  • If A is a non-singular matrix of order 3, then |adj A| = |A|^(n) here the value of n is

    A
    2
    B
    4
    C
    6
    D
    8
  • If A is a non-singular matrix of order 3, then adj(adj(A)) is equal to

    A
    `A`
    B
    `A^(-1)`
    C
    `1/(|A|)A`
    D
    `|A|A`
  • If A is a non-singular matrix of order 3, then |adjA^(3)|=

    A
    `|A|^(9)`
    B
    `|A|^(12)`
    C
    `|A|^(3)`
    D
    `|A|^(6)`
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