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If D=diag(d1,d2,d3,…,dn)" where "d ne 0"...

If `D=diag(d_1,d_2,d_3,…,d_n)" where "d ne 0" for all " I = 1,2,…,n," then " D^(-1)`is equal to

A

`diag[d_(1)^(-1), d_(2)^(-1), …., d_(n)^(-1)]`

B

`I_(n)`

C

`D`

D

`-diag[d_(1)^(-1), d_(2)^(-1), …., d_(n)^(-1)]`

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The correct Answer is:
A
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