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NIKITA PUBLICATION-MATRICES-MULTIPLE CHOICE QUESTIONS
- If the inverse of [[1, 2, x], [4, -1, 7], [2, 4, -6]] does not exist, ...
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- If [[x, 1, 1], [2, 3, 4], [1, 1, 1]] has no inverse, then x=
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- Matrix A=[[1, 0, -k], [2, 1, 3], [k, 0, 1]] is invertible for
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- If k is a scalar and I is unit matrix of order 3, then adj(kI)=
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- If a=[[-2, 6], [-5, 7]], then adjA=
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- If A=[[2, -3], [3, 5]], then adjA=
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- If A=[[2, -3], [4, 1]], then adjA=
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- If A=[[4, 2], [3, 4]], then |adjA|=
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- If X=[[-x, -y], [z, t]], then transpose of adjX is
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- Adjoint of the matrix N=[[-4, -3, -3], [1, 0, 1], [4, 4, 3]] is
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- If A=[[-1, -2, -2], [2, 1, -2], [2, -2, 1]], then adjA=
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- If A=[[3, 5, -1], [2, 0, 4], [1,-3, 0]], then [[12, 4, -6], [3, 1, 14]...
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- If A=[[1, -1, 2], [-2, 3, 5], [-2, 0, -1]], then adjA=
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- If A=[[2, 0, -1], [3, 1, 2], [-1, 1, 2]], then adjA=
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- If A=[5a-b3 2] and A adj A=AA^T , then 5a+b is equal to: (1) -1 (2) ...
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- If the adjoint of a 3 3 matrix P is 1 4 4 2 1 7 1 1 3 , then the po...
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- A=[[1, 0, 2], [-1, 1, -2], [0, 2, 1]] and adjA=[[5, x, -2], [1, 1, 0],...
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- If A=[[-1, -2, -2], [2, 1, -2], [2, -2, 1]] and kA'=adjA, then k=
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- If A is a unit matrix of order n, then A(adjA) is
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- If A=[[3, 4], [5, 7]], then A(adjA)=
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